Quote Originally Posted by Jon Ruyle
I'm not sure- by bellows factor, do you mean 1 + n, and by f (effective) do you mean f * bellows factor? If so, these two lenses have different apertures.

Yes, that's what I meant, and now I see what you're saying. But even if the apertures are the same and the DOF is the same, doesn't bellows factor mean the larger sensor will get less light (and therefore have more noise for the same DOF)?